Sourdough vs. BBQ: Super Bowl LIV thread

Wile E. Coyote knows all about that.

 

No, Wile E. is the master tunnel painter.

 

I came for the football...

There are threads that turn into the internet equivalent of that kid your mama told you to stay away from.

 

My doctor says I'm at my ideal height-weight ratio if I were 17 feet tall.

 

Media Week now includes discussions of cartoon physics relative to Andy Reid's clock management.

 

When Andy Reid punts the ball down by 4 with 2:40 to play, the parabolic path of a football can be described by these two equations:

y = Vyt - 0.5gt^2
y = Vyt - 0.5gt^2

x =Vxt
x =Vxt

• y is the height at any time (t)
• Vy is the vertical component of the football's initial velocity
• g is acceleration due to Earth's gravity, 9.8 m/s2
• x is the horizontal distance of the ball at any time (t)
• Vx is the horizontal component of the football's initial velocity

To calculate the hang-time (ttotal), peak height (ymax), and maximum range (xmax) of a punt, you must know the initial velocity (V) of the ball off the kicker's foot, and the angle (theta) of the kick.

The velocity must be broken into horizontal (Vx) and vertical (Vy) components according to the following formulas:

• Vx = V cos(theta)
• Vy = V sin(theta)

The hang-time (ttotal) must be determined by one of these two formulas:

• ttotal = (2Vy/g)
• ttotal = (0.204Vy)

Once you know the hang-time, you can calculate maximum range (xmax):

• xmax = Vx ttotal

You can calculate the time (t1/2) at which the ball is at its peak height:

• t1/2 = 0.5 ttotal

And you can calculate the peak height (ymax), using one of these two formulas:

• ymax= vy(t1/2) - 1/2g(t1/2)^2
• ymax = vy(t1/2) - 0.49(t1/2)^2

For example, a kick with a velocity of 90 ft/s (27.4 m/s) at an angle of 30 degrees will have the following values:

Vertical and horizontal components of velocity:

• Vx = V cos(theta) = (27.4 m/s) cos (30 degrees) = (27.4 m/s) (0.0.87) = 23.7 m/s
• Vy = V sin(theta) = (27.4 m/s) sin (30 degrees) = (27.4 m/s) (0.5) = 13.7 m/s

Hang-time:

• ttotal = (0.204Vy) = {0.204 (13.7m/s)} = 2.80 s.

Maximum range:

• xmax = Vx ttotal = (23.7 m/s)(2.80 s) = 66.4 m
• 1 m = 1.09 yd
• xmax = 72 yd

Time at peak height:

• t1/2 = 0.5 ttotal = (0.5)(2.80 s) = 1.40 s

Peak height:

• ymax = Vy(t1/2) - 0.49(t1/2)^2 = [{(13.7 m/s)(1.40 s)} - {0.49(1.40 s)^2}] = 18.2 m
• 1 m = 3.28 ft
• ymax = 59.7 ft

If we do the calculations for a punt with the same velocity, but an angle of 45 degrees, then we get a hang-time of 3.96 s, a maximum range of 76.8 m (84 yd), and a peak height of 36.5 m (120 ft). If we change the angle of the kick to 60 degrees, we get a hang-time of 4.84 s, a maximum range of 66.3 m (72 yd), and a peak height of 54.5 m (179 ft). Notice that as the angle of the kick gets steeper, the ball hangs longer in the air and goes higher. Also, as the angle of the kick is increased, the distance traveled by the ball increases to a maximum (achieved at 45 degrees) and then decreases.

Regardless of the hang time or distance, the Chiefs will lose the game due to the punt.

 

Either that or Lucy gets duplicitous in the 4th. /#cartoonsyo

 

too soon

 

One of the great What-Ifs ever.

 

I was told there would be no math.

 

I think you neglected to consider the effects of air resistance.

 

Corned Beef, Turkey, Roast Beef, Cole Slaw, Swiss, Russian dressing on triple decker Rye. The New Jersey Sloppy Joe. The older generation prefered beef tongue to roast beef. Tabatchnik's of West Orange and Livingston